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Cholesterol

Catalog No. T0760 CAS 57-88-5

Synonyms: Cholesterin, Cholesteryl alcohol

Purity 99.74% Datasheet MSDS

Cholesterol is the primary sterol in mammals. The significance of Cholesterol is becoming more appreciated in fundamental cellular processes.

Cholesterol, CAS 57-88-5

Pack Size	Availability	Price/USD
5 mg	In stock	16.00
10 mg	In stock	20.00
25 mg	In stock	30.00
50 mg	In stock	38.00
100 mg	In stock	43.00
200 mg	In stock	50.00
500 mg	In stock	59.00

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Purity 99.74%

HNMR HPLC COA Datasheet MSDS

Biological Description

Chemical Properties

Storage & Solubility Information

Description	Cholesterol is the primary sterol in mammals. The significance of Cholesterol is becoming more appreciated in fundamental cellular processes.
Targets&IC50	MRP1, RORα,

Synonyms	Cholesterin , Cholesteryl alcohol
Purity	99.74%
Molecular Weight	386.65
Formula	C27H46O
CAS No.	57-88-5

Storage

-20℃ 3 years powder

-80℃ 2 years in solvent

Solubility Information

Ethanol: 25 mg/mL (64.66 mM), Need ultrasonic

DMSO: 0.79 mg/mL (2.04 mM), Need warming

( < 1 mg/ml refers to the product slightly soluble or insoluble )

Citations

References and Literature

1. Wu Y, et al. Biochem Biophys Res Commun. 2015 Feb 20;457(4):614-20.

Related compound libraries

This product is contained In the following compound libraries：

Bioactive Compound Library Inhibitor Library Natural Compound Library for HTS Anti-cancer Compound Library Human Endogenous Metabolite Compound Library Ion Channel Inhibitor Library Immunology/Inflammation Compound Library Anti-Metabolism Disease Compound Library

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Method for preparing DMSO master liquid: mg drug pre-dissolved in μL DMSO (Master liquid concentration mg/mL，Please contact us first if the concentration exceeds the DMSO solubility of the batch of drug. )

Method for preparing in vivo formulation：Take μL DMSO master liquid, next add μL PEG300， mix and clarify, next add μL Tween 80，mix and clarify, next add μL ddH₂O, mix and clarify.

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What is the mass of compound required to make a 10 mM stock solution in 10 ml of water given that the molecular weight of the compound is 197.13 g/mol?
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What volume of a given 10 mM stock solution is required to make 20ml of a 50 μM solution?
Using the equation C1V1 = C2V2, where C1=10 mM, C2=50 μM, V2=20 ml and V1 is the unknown:
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Molar mass (molar weight) is the mass of one mole of a substance and is expressed in g/mol.

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Answers to questions you may have can be found in the Inhibitor Handling Instructions. Topics include how to prepare stock solutions, how to store Products, and issues that need special attention for cell-based assays and animal experiments.

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